Motivation

Recall that in chapter 1, §1.4, we studied the following question:

Question: Let $ a$ and $ b$ be any two non-zero integers. Can the set of all possible sums of multiples of $ a$ and $ b$ be described in a ``simple'' way? If so, how?

Before we recall how we answered this question, let us introduce some terminology. The `` the set of all possible sums of multiples'' of a given set of elements occurs so often in abstract algebra that it has a special name.

Definition 2.3.1   Let $ R$ be a ring and let $ a_1,...,a_k$ be elements of $ R$. The set $ I$ of all possible sums of multiples of the $ a_i$ is called the ideal of $ R$ generated by $ a_1$, ..., $ a_k$. In other words,

$\displaystyle I=\{r_1a_1+...r_ka_k\ \vert\ r_i\in R\}.
$

When there is no danger of confusion, it is often denoted $ I=(a_1,...,a_k)$.

In this terminology, the question above becomes: What is $ I=(a,b)\subset \mathbb{Z}$?

We answered the question by proving that any subset of the integers which was closed under addition and (integer) multiplication must be of the form $ c\mathbb{Z}$, for some integer $ c\geq 1$ (Lemma 1.4.2). (In fact, $ c=gcd(a,b)$.) In other words, we showed $ I=(a,b)=(c)$, where $ c=gcd(a,b)$. This may be reworded as saying, the ideal in $ \mathbb{Z}$ generated by the $ 2$ elements $ a,b$ is an ideal generated by only $ 1$ element $ c=gcd(a,b)$. Ideals generated by only one elements also have a special name.

Definition 2.3.2   Let $ R$ be a ring and let $ a$ be an element of $ R$. The set $ I$ of all possible multiples of $ a$ is called the principal ideal of $ R$ generated by $ a$. In other words,

$\displaystyle I=\{ra\ \vert\ r_i\in R\}.
$

When there is no danger of confusion, it is often denoted $ I=(a)$.

Using this terminology, we showed in chapter 1 that the ideal of $ \mathbb{Z}$ generated by $ a,b$ is a principal ideal. One can use mathematical induction to show that any ideal in $ \mathbb{Z}$ of the for $ I=(a_1,...,a_k)$ is a principal ideal. Then every ideal of a ring $ R$ is a principal ideal, then $ R$ is called a principal ideal domain. It is possible to show that the ring $ \mathbb{Z}$ is a principal ideal domain.



David Joyner 2007-09-03