Algebraic curves

To find the equations of an algebraic curve parametrized by $ x=f(t),y=g(t),z=h(t)$, where $ f,g,h$ are polynomials,

Example 2.8.13   The twisted cubic is parameterized by $ x=t$, $ y=t^2$, $ z=t^3$. The object is to find a Gröbner basis for the ideal $ I=(x-t,y-t^2,z-t^3)$ in $ \mathbb{Q}[x,y,z,t]$. Let $ <$ denote the lexicographic order defined by $ t<z<y<x$. The Gröbner basis for $ I$ is $ G=\{y-x^2,z-x^3,-x+t\}$.

Therefore the algebraic equations for the curve are

$\displaystyle y=x^2,\ z=x^3.
$

Example 2.8.14   Let $ x=t^2+2t-5$, $ y=t^4+4 t^3 +7 t^2 + 6 t-4$, $ z=100 - 70 t - 23 t^2 + 12 t^3 + 3 t^4$ yields the ideal $ I=( x - t^2-2t+5, y- t^4-4t^3-7t^2-6t+4,
z - 100 + 70 t + 23 t^2 - 12 t^3 -3 t^4 )$ which has the Grobner basis $ \{-32 - 13x - x^2 + y, 5 x - 3 x^2 + z, 5 - 2 t - t^2 + x\}$. So the equations for the curve are $ y = x^2+13x+32$, and $ z= 3x^2-5x$.



David Joyner 2007-09-03